For a reversible heat engine, efficiency is expressed as
1-(T2/T1) = 1- (Q2/Q1)
2 represents sink, where heat is rejected out.
Thus, in the given data, T1=600 K , (Source at higher temperature) T2 = 300 K (sink), heat rejected out , Q2 = 200kJ . So
Efficiency = 1-(0.5) = 0.5 = (Q1-Q2)/Q1. This gives heat input Q1 to be 400 kJ.
2) A reversible heat engine operates between 300K and 600K. If heat output is 200 KJ, the heat input is
400 kJ
Related ISRO Technical Assistant Mechanical Question Paper - 2016 with Answer Key
all of these combined
The Bernoulli's equation states that For a perfect incompressible liquid, flowing in a continuous stream, the total energy of a particle remains the same, while the particle moves from one point to another.
The Bernoulli's equation is applied to venturimeter, orifice meter and pitot tube.
Hence Bernoulli's theorem applies to incompressible, steady and non-viscous flow.
pd/4t
Tensile stress in thin spherical shell subjected to internal pressure is pd/4t
vapour
Simply defined, cavitation is the formation of bubbles or cavities in liquid, developed in areas of relatively low pressure around an impeller. The imploding or collapsing of these bubbles trigger intense shockwaves inside the pump, causing significant damage to the impeller and/or the pump housing.
Hence cavitation in a pump is associated with vapour pressure.
Otto cycle
Otto cycle is also known as constant volume cycle, as the heat is received and rejected at a constant volume. Otto cycle is used in gas, petrol and many of the oil engines. The petrol engine works on Otto cycle.
The ideal Otto cycle consists of two constant volume and two reversible adiabatic or isentropic processes.
Otto cycle is taken as a standard of comparison for internal combustion engines. For the purpose of comparison with other cycles, the air is assumed to be the working substance.